I have a hex color, eg #F4F8FB
(or rgb(244, 248, 251)
) that I want converted into an as-transparent-as-possible rgba color (when displayed over white).(我有一个十六进制颜色,例如#F4F8FB
(或rgb(244, 248, 251)
#F4F8FB
rgb(244, 248, 251)
),我想将其转换为尽可能透明的 rgba颜色(当显示为白色时)。)
Make sense?(说得通?) I'm looking for an algorithm, or at least idea of an algorithm for how to do so.(我正在寻找一种算法,或者至少是关于一种算法的构想。)
For Example:(例如:)
rgb( 128, 128, 255 ) --> rgba( 0, 0, 255, .5 )
rgb( 152, 177, 202 ) --> rgba( 50, 100, 150, .5 ) // can be better(lower alpha)
Ideas?(有想法吗?)
FYI solution based on Guffa's answer:(基于Guffa答案的FYI解决方案:)
function RGBtoRGBA(r, g, b){
if((g == null) && (typeof r === 'string')){
var hex = r.replace(/^s*#|s*$/g, '');
if(hex.length === 3){
hex = hex.replace(/(.)/g, '$1$1');
}
r = parseInt(hex.substr(0, 2), 16);
g = parseInt(hex.substr(2, 2), 16);
b = parseInt(hex.substr(4, 2), 16);
}
var min, a = (255 - (min = Math.min(r, g, b))) / 255;
return {
r : r = 0|(r - min) / a,
g : g = 0|(g - min) / a,
b : b = 0|(b - min) / a,
a : a = (0|1000*a)/1000,
rgba : 'rgba(' + r + ', ' + g + ', ' + b + ', ' + a + ')'
};
}
RGBtoRGBA(204, 153, 102) == RGBtoRGBA('#CC9966') == RGBtoRGBA('C96') ==
{
r : 170,
g : 85 ,
b : 0 ,
a : 0.6,
rgba : 'rgba(170, 85, 0, 0.6)'
}
ask by Mark Kahn translate from so