javascript - Javascript数组：删除另一个数组中包含的所有元素(Javascript arrays: remove all elements contained in another array)

Question

I am looking for an efficient way to remove all elements from a javascript array if they are present in another array.(我正在寻找一种有效的方法来从javascript数组中删除所有元素（如果它们存在于另一个数组中）。)

// If I have this array: var myArray = ['a', 'b', 'c', 'd', 'e', 'f', 'g']; // and this one: var toRemove = ['b', 'c', 'g']; I want to operate on myArray to leave it in this state: ['a', 'd', 'e', 'f'](我想对myArray进行操作，以使其保持这种状态： ['a', 'd', 'e', 'f']) With jQuery, I'm using grep() and inArray() , which works well:(使用jQuery，我使用的是grep()和inArray() ，效果很好：) myArray = $.grep(myArray, function(value) { return $.inArray(value, toRemove) < 0; }); Is there a pure javascript way to do this without looping and splicing?(有没有这样做而不循环和拼接的纯JavaScript方法？)   ask by Tap translate from so

Answer 1

Use the Array.filter() method:(使用Array.filter()方法：)

myArray = myArray.filter( function( el ) { return toRemove.indexOf( el ) < 0; } ); Small improvement, as browser support for Array.includes() has increased:(由于浏览器对Array.includes()支持增加了Array.includes()小改进：) myArray = myArray.filter( function( el ) { return !toRemove.includes( el ); } ); Next adaptation using arrow functions :(使用箭头功能的下一个适应：) myArray = myArray.filter( ( el ) => !toRemove.includes( el ) );