c - 如何使用printf格式化unsigned long long int？(How do you format an unsigned long long int using printf?)

Question

#include <stdio.h>
int main() {
    unsigned long long int num = 285212672; //FYI: fits in 29 bits
    int normalInt = 5;
    printf("My number is %d bytes wide and its value is %ul. A normal number is %d.
", sizeof(num), num, normalInt);
    return 0;
}

Output:

(输出：)

My number is 8 bytes wide and its value is 285212672l. A normal number is 0.

I assume this unexpected result is from printing the unsigned long long int .

(我认为这种意外的结果是由于打印unsigned long long int 。)

How do you printf() an unsigned long long int ?

(你如何printf()一个unsigned long long int ？)

  ask by andrewrk translate from so

Answer 1

Use the ll (el-el) long-long modifier with the u (unsigned) conversion.

(将ll（el-el）long-long修饰符与u（无符号）转换一起使用。)

(Works in windows, GNU).

(（在Windows，GNU中运行）。)

printf("%llu", 285212672);