I have a list of lists ( and each list of my list contain another list). When trying to read that list, I get this error :
File "execution/fil_test.py", line 105, in <module>
F, M = fil_dico_tr (c, s, l_1, list_of_lexicon_tr)
File "/home/getalp/kelodjoe/eXP/Dossier_rules/filtrage_test/filtrage_f_tr.py", line 79, in fil_dico_tr
if w in i_lexicon[0][0][0] or w in i_lexicon[0][1][0] or w in i_lexicon[0][2][0] :
IndexError: list index out of range
I am looking inside each list of list of list to see if the word is present but there is this error of last index.
When I print the len of each list I get the length so I do not understand why Python display "list out of range a serror'
Code :
i_lexicon = [
[[liste_neg_D_g, liste_pos_D_g], [liste_neg_A, liste_pos_A], [liste_neg_P, liste_pos_P]],
[[liste_neg_A, liste_pos_A], [liste_neg_F, liste_pos_F], [liste_neg_P, liste_pos_P]],
[[liste_neg_D_g, liste_pos_D_g], [liste_neg_F, liste_pos_F],[liste_neg_P, liste_pos_P]],
[[liste_neg_D_g, liste_pos_D_g], [liste_neg_A, liste_pos_A],[liste_neg_F, liste_pos_F]]
]
F, M = fil_dico_tr (c, s, l_1, list_of_lexicon_tr)
v = "Je marche dans la rue et je ne sais pas mais je crois que la famille est loin de la maison"
c ="mais"
for i, j in enumerate(v):
if j == c:
liste_index_pivot.append(i)
if len(liste_index_pivot)== 0:
#print(k)
list_sans_mais.append(k)
for w in v:
ind_pivot = max(liste_index_pivot)
#print(ind_pivot)
ind = v.index(w)
# AVANT LE CONNECTEUR
if ind < ind_pivot:
if w in i_lexicon[0][0][0] or w in i_lexicon[0][1][0] or w in i_lexicon[0][2][0] :
d_neg_av[w] = ind - ind_v
elif w in i_lexicon[0][0][1] or w in i_lexicon[0][1][1] or w in i_lexicon[0][2][1] :
d_pos_av[w] = ind - ind_v
else:
d_0_av[w] = 0
# APRèS LE CONNECTEUR
elif ind > ind_pivot:
if w in i_lexicon[0][0][0] or w in i_lexicon[0][1][0] or w in i_lexicon[0][2][0] :
d_neg_ap[w] = ind + ind_v
elif w in i_lexicon[0][0][1] or w in i_lexicon[0][1][1] or w in i_lexicon[0][2][1] :
d_pos_ap[w] = ind - ind_v * 2
else:
d_0_ap[w] = 0
else:
None
question from:
https://stackoverflow.com/questions/66061698/accessing-an-element-of-a-list1-contain-in-another-list-2-which-is-contain-i 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…