c++ - when we write void variable like void *p ; cout<<&p; cout<<p; so it give two different address but why?

Question

C++ output give two different address but why complier give two address instead of I am writing only one variable

void *p ;
cout<<&p<<p;

question from:https://stackoverflow.com/questions/66046233/when-we-write-void-variable-like-void-p-coutp-coutp-so-it-give-two-dif

Answer 1

void *p ; is an uninitialized pointer. So what you will have inside the pointer there is actual garbage. When you do &p, your returning the address of the pointer p. That's why they both return different values.