Pointers and access to memory in c. Be careful

Question

(This question already has answers here): question from:https://stackoverflow.com/questions/54025987/pointers-and-access-to-memory-in-c-be-careful

Answer 1

In this case:

char *str = "Sometimes I feel like I'm going crazy.";

You're initializing str to contain the address of the given string literal. You're not actually dereferencing anything at this point.

This is also fine:

char *str;
str = "Sometimes I feel like I'm going crazy.";

Because you're assigning to str and not actually dereferencing it.

This is a problem:

int *pt;
*pt = 606;

Because pt is not initialized and then it is dereferenced.

You also can't do this for the same reason (plus the types don't match):

*pt= &myVariable;

But you can do this:

pt= &myVariable;

After which you can freely use *pt.