python - Scope of variable within "with" statement?

Question

I am reading only firstline from python using :

with open(file_path, 'r') as f:
    my_count = f.readline()
print(my_count)

I am bit confused over scope of variable my_count. Although prints work fine, would it be better to do something like my_count = 0 outside with statement first (for eg in C in used to do int my_count = 0)

question from:https://stackoverflow.com/questions/45100271/scope-of-variable-within-with-statement

Answer 1

A with statement does not create a scope (like if, for and while do not create a scope either).

As a result, Python will analyze the code and see that you made an assignment in the with statement, and thus that will make the variable local (to the real scope).

In Python variables do not need initialization in all code paths: as a programmer, you are responsible to make sure that a variable is assigned before it is used. This can result in shorter code: say for instance you know for sure that a list contains at least one element, then you can assign in a for loop. In Java assignment in a for loop is not considered safe (since it is possible that the body of the loop is never executed).

Initialization before the with scope can be safer in the sense that after the with statement we can safely assume that the variable exists. If on the other hand the variable should be assigned in the with statement, not initializing it before the with statement actually results in an additional check: Python will error if somehow the assignment was skipped in the with statement.

A with statement is only used for context management purposes. It forces (by syntax) that the context you open in the with is closed at the end of the indentation.