bash - Pass args for script when going thru pipe

Question

I have this example shell script:

echo /$1/

So I may call

$ . ./script 5
# output: /5/

I want to pipe the script into sh(ell), but can I pass the arg too ?

cat script | sh 
# output: //

question from:https://stackoverflow.com/questions/14693100/pass-args-for-script-when-going-thru-pipe

Answer 1

You can pass arguments to the shell using the -s option:

cat script | bash -s 5