If both arrays are in the correct order; where each item corresponds to its associated member identifier then you can simply use.
var merge = _.merge(arr1, arr2);
Which is the short version of:
var merge = _.chain(arr1).zip(arr2).map(function(item) {
return _.merge.apply(null, item);
}).value();
Or, if the data in the arrays is not in any particular order, you can look up the associated item by the member value.
var merge = _.map(arr1, function(item) {
return _.merge(item, _.find(arr2, { 'member' : item.member }));
});
You can easily convert this to a mixin. See the example below:
_.mixin({
'mergeByKey' : function(arr1, arr2, key) {
var criteria = {};
criteria[key] = null;
return _.map(arr1, function(item) {
criteria[key] = item[key];
return _.merge(item, _.find(arr2, criteria));
});
}
});
var arr1 = [{
"member": 'ObjectId("57989cbe54cf5d2ce83ff9d6")',
"bank": 'ObjectId("575b052ca6f66a5732749ecc")',
"country": 'ObjectId("575b0523a6f66a5732749ecb")'
}, {
"member": 'ObjectId("57989cbe54cf5d2ce83ff9d8")',
"bank": 'ObjectId("575b052ca6f66a5732749ecc")',
"country": 'ObjectId("575b0523a6f66a5732749ecb")'
}];
var arr2 = [{
"member": 'ObjectId("57989cbe54cf5d2ce83ff9d8")',
"name": 'yyyyyyyyyy',
"age": 26
}, {
"member": 'ObjectId("57989cbe54cf5d2ce83ff9d6")',
"name": 'xxxxxx',
"age": 25
}];
var arr3 = _.mergeByKey(arr1, arr2, 'member');
document.body.innerHTML = JSON.stringify(arr3, null, 4);
body { font-family: monospace; white-space: pre; }
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