I'm trying to implement Longest Common Subsequence algorithm in c, the matrices c[][] stores the length of the longest common subsequence, row[][] stores the parent block row in the c[][] matrix and col[][] stores the parent block column.
I apologise for the downright inconvenient and inefficient approach in solving LCS but
nothing is getting printed. Please help.
#include<stdio.h>
#include<stdlib.h>
void lcs(char *a,char *b,int i,int j)
{
int x,y,z;
int **c=(int **)malloc((j+1)*sizeof(int *));
for(x=0;x<j+1;x++)
{
*(c+x)=(int *)malloc((i+1)*sizeof(int));
*(*(c+x)+0)=0;
}
for(y=0;y<i+1;i++)
c[0][y]=0;
int **row=(int **)malloc((j+1)*sizeof(int *));
for(x=0;x<j+1;x++)
{
*(row+x)=(int *)malloc((i+1)*sizeof(int));
*(*(row+x)+0)=x-1;
}
for(y=0;y<i+1;y++)
row[0][y]=0;
row[0][0]=0;
int **col=(int **)malloc((j+1)*sizeof(int *));
for(x=0;x<j+1;x++)
{
*(col+x)=(int *)malloc((i+1)*sizeof(int));
*(*(col+x)+0)=0;
}
for(y=0;y<i+1;y++)
col[0][y]=y-1;
col[0][0]=0;
for(x=1;x<j+1;x++)
{
for(y=1;y<i+1;y++)
{
if(a[y-1]==b[x-1])
{
c[x][y]=c[x-1][y-1]+1;
row[x][y]=x-1;
col[x][y]=y-1;
}
else if(c[x-1][y]>
c[x][y-1])
{
c[x][y]=c[x-1][y];
row[x][y]=x-1;
col[x][y]=y;
}
else
{
c[x][y]=c[x][y-1];
row[x][y]=x;
col[x][y]=y-1;
}
}
}
for(x=0;x<j+1;x++)
{
for(y=0;y<i+1;y++)
printf("%d ",c[x][y]);
printf("
");
}
printf("
");
for(x=0;x<j+1;x++)
{
for(y=0;y<i+1;y++)
printf("%d,%d ",row[x][y],col[x][y]);
printf("
");
}
}
void main()
{
char a[30]="papayaman";
char b[30]="papmn";
lcs(a,b,9,5);
}
question from:
https://stackoverflow.com/questions/65872923/longest-common-subsequence-not-printing-length-matrix 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…