Python print different output if change order of if else

Question

Closed. This question needs to be more focused. It is not currently accepting answers. question from:https://stackoverflow.com/questions/65838537/python-print-different-output-if-change-order-of-if-else

Answer 1

Because the the code start checking from the if part and then goes further elif parts if the previous one is false.

Basically, the number which is divisible by both 3 and 5 will meet the first if logic as it is divisible by 3 also in your second code, so it will execute that if and won't go further.

Here this code will execute like :

1. first it will check if(number%3 == 0), if it is true then it will print("Fizz") and rest of the elif and else will not be checked.
2. If 1 is not true then it will check elif(number%5 == 0)
3. Then by this way it will go down.

if(number % 3 == 0):
        print("Fizz")
    elif(number % 5 == 0):
        print("Buzz")
    elif(number % 3 == 0 and number % 5 == 0): #this line not use first and output never have "fizzbuzz"
        print("FizzBuzz")
    else:
        print(number)