RegEx: Grabbing values between quotation marks

Question

I have a value like this:

"Foo Bar" "Another Value" something else

What regex will return the values enclosed in the quotation marks (e.g. Foo Bar and Another Value)?

Answer 1

I've been using the following with great success:

(["'])(?:(?=(\?))2.)*?1

It supports nested quotes as well.

For those who want a deeper explanation of how this works, here's an explanation from user ephemient:

([""']) match a quote; ((?=(\?))2.) if backslash exists, gobble it, and whether or not that happens, match a character; *? match many times (non-greedily, as to not eat the closing quote); 1 match the same quote that was use for opening.