grep 'potato:' file.txt | sed 's/^.*: //'
grep
looks for any line that contains the string potato:
, then, for each of these lines, sed
replaces (s///
- substitute) any character (.*
) from the beginning of the line (^
) until the last occurrence of the sequence :
(colon followed by space) with the empty string (s/...//
- substitute the first part with the second part, which is empty).
or
grep 'potato:' file.txt | cut -d -f2
For each line that contains potato:
, cut
will split the line into multiple fields delimited by space (-d
- d
= delimiter,
= escaped space character, something like -d" "
would have also worked) and print the second field of each such line (-f2
).
or
grep 'potato:' file.txt | awk '{print $2}'
For each line that contains potato:
, awk
will print the second field (print $2
) which is delimited by default by spaces.
or
grep 'potato:' file.txt | perl -e 'for(<>){s/^.*: //;print}'
All lines that contain potato:
are sent to an inline (-e
) Perl script that takes all lines from stdin
, then, for each of these lines, does the same substitution as in the first example above, then prints it.
or
awk '{if(/potato:/) print $2}' < file.txt
The file is sent via stdin
(< file.txt
sends the contents of the file via stdin
to the command on the left) to an awk
script that, for each line that contains potato:
(if(/potato:/)
returns true if the regular expression /potato:/
matches the current line), prints the second field, as described above.
or
perl -e 'for(<>){/potato:/ && s/^.*: // && print}' < file.txt
The file is sent via stdin
(< file.txt
, see above) to a Perl script that works similarly to the one above, but this time it also makes sure each line contains the string potato:
(/potato:/
is a regular expression that matches if the current line contains potato:
, and, if it does (&&
), then proceeds to apply the regular expression described above and prints the result).