c++ - Return a 2d array from a function

Question

Hi I am a newbie to C++ I am trying to return a 2d array from a function. It is something like this

int **MakeGridOfCounts(int Grid[][6])
{
  int cGrid[6][6] = {{0, }, {0, }, {0, }, {0, }, {0, }, {0, }};

  return cGrid;
}

Answer 1

This code returns a 2d array.

 #include <cstdio>

    // Returns a pointer to a newly created 2d array the array2D has size [height x width]

    int** create2DArray(unsigned height, unsigned width)
    {
      int** array2D = 0;
      array2D = new int*[height];
    
      for (int h = 0; h < height; h++)
      {
            array2D[h] = new int[width];
    
            for (int w = 0; w < width; w++)
            {
                  // fill in some initial values
                  // (filling in zeros would be more logic, but this is just for the example)
                  array2D[h][w] = w + width * h;
            }
      }
    
      return array2D;
    }
    
    int main()
    {
      printf("Creating a 2D array2D
");
      printf("
");
    
      int height = 15;
      int width = 10;
      int** my2DArray = create2DArray(height, width);
      printf("Array sized [%i,%i] created.

", height, width);
    
      // print contents of the array2D
      printf("Array contents: 
");
    
      for (int h = 0; h < height; h++)
      {
            for (int w = 0; w < width; w++)
            {
                  printf("%i,", my2DArray[h][w]);
            }
            printf("
");
      }
    
          // important: clean up memory
          printf("
");
          printf("Cleaning up memory...
");
          for (int h = 0; h < height; h++) // loop variable wasn't declared
          {
            delete [] my2DArray[h];
          }
          delete [] my2DArray;
          my2DArray = 0;
          printf("Ready.
");
    
      return 0;
    }