I'm using the datetime
module, i.e.:
>>> import datetime
>>> today = datetime.datetime.now()
>>> print(today)
2009-03-06 13:24:58.857946
and I would like to compute the day of year that takes leap years into account. e.g. today (March 6, 2009) is the 65th day of 2009.
I see a two options:
Create a number_of_days_in_month = [31, 28, ...]
array, decide if it's a leap year and manually sum up the days.
Use datetime.timedelta
to make a guess & then binary search for the correct day of the year:
>>> import datetime
>>> YEAR = 2009
>>> DAY_OF_YEAR = 62
>>> d = datetime.date(YEAR, 1, 1) + datetime.timedelta(DAY_OF_YEAR - 1)
These both feel pretty clunky & I have a gut feeling that there's a more "Pythonic" way of calculating the day of the year. Any ideas/suggestions?
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