Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
372 views
in Technique[技术] by (71.8m points)

user interface - How to do page navigation for many, many pages? Logarithmic page navigation

What's the best way of displaying page navigation for many, many pages?

(Initially this was posted as a how-to tip with my answer included in the question. I've now split my answer off into the "answers" section below).


To be more specific:

Suppose you're displaying a set of records to the user, broken up into fixed-size pages (like the results of a Google search, for example). If there are only a few pages, you can display a page navigation area at the end of the results that might look like this:

[ << ] [<] 1 2 3 4 5 6 7 8 9 10 11 12 13 [ > ] [ >> ]

But this quickly becomes unweildy if there are much more than 20 or 30 pages of results.

Sometimes you'll see things like this:

[ << ] [<] ... 665 666 667 668 669 670 671 672 673 ... [ > ] [ >> ]

or this:

[ << ] [<] 1 2 3 ... 667 668 669 670 671 ... 845 846 847 [ > ] [ >> ]

but in both cases, navigating to anywhere in the middle of the "..." sections would take many, many mousclicks. Sometimes an input box for entering the page number directly is provided; otherwise (assuming we're talking about a webpage here) the savvy user is likely to look at the URL to see if they can edit it directly.

What would be nice would be to have a pagination display that lets the user reach any page in only a few mouseclicks, without having ridiculously many links.

How would that best be achieved?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Here's my solution - use "Logarithmic Page Navigation":

This can be achieved by having page numbers distributed logarithmically, according to distance from either the endpoints or the current page. Here's an example of what I mean:

1 2 3 4 5 6 . 10 . 20 . 30 . 40 . 50 .. 100 .. 200 . 210 . 220 . 230 . 240 . 250 . 252 253 254 255 256 257 258 259 260 261 262 . 270 . 280 . 290 . 300 . 310 .. 400 .. 500 .. 600 .. 700 .. 800 .. 900 .. 950 . 960 . 970 . 980 . 990 . 995 996 997 998 999 1000

Notice how in the gaps, numbering goes from 1s, to 10s, to 100s (etc.). (I use powers of 10, but in principle you could use a different scheme - powers of 2, say).

I wrote some code that does this back in 2004, and thought I'd share it here. There are PHP and ASP versions, but the logic ought to be simple to translate into any language. Note that the bit at the bottom (in both cases) just displays some examples. Obviously the formatting will need customization to match your webpage (or application), so it's pretty basic here. Alter LINKS_PER_STEP in paginationHTML to determine how many numbers get displayed before the step size increases, as you move away from the endpoints or current page.

For a more compact output you could also consider altering the code so that the numbering is not "dense" around the endpoints (i.e. dense only around the current page).

Here's the code:

PHP version:

<?

// Used by paginationHTML below...
function paginationLink($p, $page, $URL)
{
  if ($p==$page) return '<b style="color:#C0C0C0">' . $p . '</b>';
  return '<a href="' . $URL . $p . '">' . $p . '</a>';
}


// Used by paginationHTML below...
function paginationGap($p1, $p2)
{
  $x = $p2-$p1;
  if ($x==0) return '';
  if ($x==1) return ' ';
  if ($x<=10) return ' . ';
  if ($x<=100) return ' .. ';
  return ' ... ';
}


// URL requires the $page number be appended to it.
// e.g. it should end in '&page=' or something similar.
function paginationHTML($page, $lastPage, $URL)
{
  $LINKS_PER_STEP = 5;

  // Nav buttons

  if ($page>1)
    $result = '<form action="' . $URL . '1" method="POST" style="display:inline"><input type="submit" value="&nbsp;|&lt;&nbsp;"></form>&nbsp;' .
              '<form action="' . $URL . ($page-1) . '" method="POST" style="display:inline"><input type="submit" value="&nbsp;&lt;&nbsp;"></form>';
  else $result = '<input type="button" value="&nbsp;|&lt;&nbsp;" disabled>&nbsp;<input type="button" value="&nbsp;&lt;&nbsp;" disabled>';

  $result .= '&nbsp;&nbsp;' . $page . '&nbsp;&nbsp;';
  if ($page<$lastPage)
    $result .= '<form action="' . $URL . ($page+1) . '" method="POST" style="display:inline"><input type="submit" value="&nbsp;&gt;&nbsp;"></form>&nbsp;' .
               '<form action="' . $URL . $lastPage . '" method="POST" style="display:inline"><input type="submit" value="&nbsp;&gt;|&nbsp;"></form>';
  else $result .= '<input type="button" value="&nbsp;&gt;&nbsp;" disabled>&nbsp;<input type="button" value="&nbsp;&gt;|&nbsp;" disabled>';
  $result .= "<br>";

  // Now calculate page links...

  $lastp1 = 1;
  $lastp2 = $page;
  $p1 = 1;
  $p2 = $page;
  $c1 = $LINKS_PER_STEP+1;
  $c2 = $LINKS_PER_STEP+1;
  $s1 = '';
  $s2 = '';
  $step = 1;
  while (true)
  {
    if ($c1>=$c2)
    {
      $s1 .= paginationGap($lastp1,$p1) . paginationLink($p1,$page,$URL);
      $lastp1 = $p1;
      $p1 += $step;
      $c1--;
    }
    else
    {
      $s2 = paginationLink($p2,$page,$URL) . paginationGap($p2,$lastp2) . $s2;
      $lastp2 = $p2;
      $p2 -= $step;
      $c2--;
    }
    if ($c2==0)
    {
      $step *= 10;
      $p1 += $step-1;         // Round UP to nearest multiple of $step
      $p1 -= ($p1 % $step);
      $p2 -= ($p2 % $step);   // Round DOWN to nearest multiple of $step
      $c1 = $LINKS_PER_STEP;
      $c2 = $LINKS_PER_STEP;
    }
    if ($p1>$p2)
    {
      $result .= $s1 . paginationGap($lastp1,$lastp2) . $s2;
      if (($lastp2>$page)||($page>=$lastPage)) return $result;
      $lastp1 = $page;
      $lastp2 = $lastPage;
      $p1 = $page+1;
      $p2 = $lastPage;
      $c1 = $LINKS_PER_STEP;
      $c2 = $LINKS_PER_STEP+1;
      $s1 = '';
      $s2 = '';
      $step = 1;
    }
  }
}

?>

<br><br><br>
<?=paginationHTML(1,1,'?page=')?>

<br><br><br>
<?=paginationHTML(2,3,'?page=')?>

<br><br><br>
<?=paginationHTML(3,3,'?page=')?>

<br><br><br>
<?=paginationHTML(73,100,'?page=')?>

<br><br><br>
<?=paginationHTML(4,100,'?page=')?>

<br><br><br>
<?=paginationHTML(257,1000,'?page=')?>

<br><br><br>
<?=paginationHTML(7062,10555,'?page=')?>

<br><br><br>
<?=paginationHTML(22080,503456,'?page=')?>

ASP version:

<%

' Used by paginationHTML below...
Function paginationLink(p, page, URL)
  if p=page then
    paginationLink = "<b style=""color:#C0C0C0"">" & p & "</b>"
  else
    paginationLink = "<a href=""" & URL & p & """>" & p & "</a>"
  end if
End Function


' Used by paginationHTML below...
Function paginationGap(p1, p2)
  Dim x
  x = p2-p1
  if x=0 then
    paginationGap = ""
  elseif x=1 then
    paginationGap = " "
  elseif x<=10 then
    paginationGap = " . "
  elseif x<=100 then
    paginationGap = " .. "
  else
    paginationGap = " ... "
  end if
End Function


' URL requires the page number be appended to it.
' e.g. it should end in "&page=" or something similar.
Function paginationHTML(page, lastPage, URL)
  const LINKS_PER_STEP = 5
  Dim p1, p2, c1, c2, s1, s2, lastp1, lastp2, step

  ' Nav buttons
  if page>1 then
    paginationHTML = "<form action=""" & URL & "1"" method=""POST"" style=""display:inline""><input type=""submit"" value=""&nbsp;|&lt;&nbsp;""></form>&nbsp;" & _
                    "<form action=""" & URL & (page-1) & """ method=""POST"" style=""display:inline""><input type=""submit"" value=""&nbsp;&lt;&nbsp;""></form>"
  else
    paginationHTML = "<input type=""button"" value=""&nbsp;|&lt;&nbsp;"" disabled>&nbsp;<input type=""button"" value=""&nbsp;&lt;&nbsp;"" disabled>"
  end if
  paginationHTML = paginationHTML & "&nbsp;&nbsp;" & page & "&nbsp;&nbsp;"
  if page<lastPage then
    paginationHTML = paginationHTML & "<form action=""" & URL & (page+1) & """ method=""POST"" style=""display:inline""><input type=""submit"" value=""&nbsp;&gt;&nbsp;""></form>&nbsp;" & _
                                    "<form action=""" & URL & lastPage & """ method=""POST"" style=""display:inline""><input type=""submit"" value=""&nbsp;&gt;|&nbsp;""></form>"
  else
    paginationHTML = paginationHTML & "<input type=""button"" value=""&nbsp;&gt;&nbsp;"" disabled>&nbsp;<input type=""button"" value=""&nbsp;&gt;|&nbsp;"" disabled>"
  end if
  paginationHTML = paginationHTML & "<br>"

  ' Now calculate page links...

  lastp1 = 1
  lastp2 = page
  p1 = 1
  p2 = page
  c1 = LINKS_PER_STEP+1
  c2 = LINKS_PER_STEP+1
  s1 = ""
  s2 = ""
  step = 1
  do
    if c1>=c2 then
      s1 = s1 & paginationGap(lastp1, p1) & paginationLink(p1, page, URL)
      lastp1 = p1
      p1 = p1+step
      c1 = c1-1
    else
      s2 = paginationLink(p2, page, URL) & paginationGap(p2, lastp2) & s2
      lastp2 = p2
      p2 = p2-step
      c2 = c2-1
    end if
    if c2=0 then
      step = step*10
      p1 = p1+step-1         ' Round UP to nearest multiple of step
      p1 = p1-(p1 mod step)
      p2 = p2-(p2 mod step)  ' Round DOWN to nearest multiple of step
      c1 = LINKS_PER_STEP
      c2 = LINKS_PER_STEP
    end if
    if p1>p2 then
      paginationHTML = paginationHTML & s1 & paginationGap(lastp1, lastp2) & s2
      if (lastp2>page) or (page>=lastPage) then exit do
      lastp1 = page
      lastp2 = lastPage
      p1 = page+1
      p2 = lastPage
      c1 = LINKS_PER_STEP
      c2 = LINKS_PER_STEP+1
      s1 = ""
      s2 = ""
      step = 1
    end if
  loop
End Function

%>


<br><br><br>
<%=paginationHTML(1,1,"?page=")%>

<br><br><br>
<%=paginationHTML(2,3,"?page=")%>

<br><br><br>
<%=paginationHTML(3,3,"?page=")%>

<br><br><br>
<%=paginationHTML(73,100,"?page=")%>

<br><br><br>
<%=paginationHTML(4,100,"?page=")%>

<br><br><br>
<%=paginationHTML(257,1000,"?page=")%>

<br><br><br>
<%=paginationHTML(7062,10555,"?page=")%>

<br><br><br>
<%=paginationHTML(22080,503456,"?page=")%>

Javascript version (within complete test page):

<!doctype html>
<html>
<head>
  <title>Logarithmic Pagination Demo</title>
  <style>

body {background:#C0C0C0;font-family:Arial,Helvetica,sans-serif;font-size:16px;text-align:left}
div {margin:0;padding:0}
div#setupDiv {margin:40px;text-align:center}
table#datarows {border-collapse:collapse;margin:40px auto}
table#datarows th {padding:5px 10px;background:#80B0FF;color:#FFFFFF;border:2px solid #80B0FF;width:1000px;text-align:center}
table#datarows td {padding:2px 10px;background:#FFFFFF;color:#D0D0D0;border:2px solid #80B0FF;width:1000px;text-align:left;font-style:italic}
input.err {border:2px solid #FF0000;background-color:#FFF0F0}
form.pager {display:table;margin:0 auto;padding:20px;border:2px solid #E0E0E0;border-radius:10px;background-color:#D0D0D0;text-align:left;white-space:nowrap}
form#pager1 {margin-top:40px}
form#pager2 {margin-bottom:60px}
form.pager div {display:table-cell;vertical-align:middle;padding:0 20px;white-space:nowrap}
form.pager div + div {border-left:2px solid #E0E0E0}
form.pager div.plinks {padding:0;border:0 none;font-size:14px;line-height:24px;max-width:800px;white-space:normal}
form.pager div.plinks b {display:inline-block;vertical-align:bottom;font-size:24px;line-height:21px;height:24px;overflow:hidden;color:#808080}
form.pager div.plinks a {text-decoration:none;color:black}
form.pager div.plinks a:hover {color:#0000FF;font-weight:bold}
form.pager div.plinks + div {border:0 none}

  </style>
  <script>

var NumPages, RecsPerPage, els1, els2, plinks1, plinks2;

function setupClick()
{
  var el, n, r;
  el = document.getElementById("NumPages");
  el.className = ((n = (el.value >>> 0)) ? "" : "err");
  el = document.getElementById("RecsPerPage");
  el.className = ((r = (el.value >>> 0)) ? "" : "err");
  if (n&&r) { NumPages = n; RecsPerPage = r; setupServerPage(); }
}

// This function sets up what would normally be part of the server's HTML output.
function setupServerPage()
{
  var totRecs = NumPages * RecsPerPage, tbdy = document.getElementById("datarows").tBodies[0], l = tbdy.rows.length;
  document.getElementById("plength1").innerHTML = document.getElementById("plength2").innerHTML = totRecs + " reco

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...