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下列程序(m转换为n进制)的时间复杂度是多少,为什么?

SeqStack* convertToType(int number, int type) {

SeqStack* stack = new SeqStack;
stack->top = -1;
while (number != 0) {
    int rest = number % type;
    if (stack->top < 99) {
        stack->data[++stack->top] = rest;
    }
    else {
        cout << "out of memery";
    }
    number = (number - rest) / type;
}
return stack;

}


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