regex - Regexp or Grep in Bash

Question

Can you please tell me how to get the token value correctly? At the moment I am getting: "1jdq_dnkjKJNdo829n4-xnkwe",258],["FbtResult

   echo '{"facebookdotcom":true,"messengerdotcom":false,"workplacedotcom":false},827],["DTSGInitialData",[],{"token":"aaaaaaa"},258],["FbtResult' | sed -n 's/.*"token":([^}]*)}/1/p'

Answer 1

You need to match the full string, and to get rid of double quotes, you need to match a " before the token and use a negated bracket expression [^"] instead of [^}]:

sed -n 's/.*"token":"([^"]*).*/1/p'

Details:

• .* - any zero or more chars
• "token":" - a literal "token":" string
• ([^"]*) - Group 1 (1 refers to this value): any zero or more chars other than "
• .* - any zero or more chars.