curl 返回值 000

Question

#!/bin/sh
# 获取tomcat进程ID  /data2/tomcat
TomcatID=$(ps -ef|grep apachepintuan|grep -w 'tomcat'|grep -v 'grep'|awk '{print $2}')  
# tomcat启动程序(这里注意tomcat实际安装的路径)  
StartTomcat=/data2/tomcat/bin/startup.sh 
# 定义要监控的页面地址  
WebUrl=http://localhost/homePageIcon.do
# 日志输出 
TomcatMonitorLog=/data2/log/TomcatMonitor.log  

Monitor()
{  
  echo "[info]开始监控tomcat...[$(date +'%F %H:%M:%S')]"
  
  # 这里判断TOMCAT进程是否存在 

  if [[ $TomcatID ]];then  

    echo "[info]当前tomcat进程ID为:$TomcatID,继续检测页面..."  

    # 检测是否启动成功(成功的话页面会返回状态"200")  

    TomcatServiceCode=$(curl -s -o $GetPageInfo -m 10 --connect-timeout 10 $WebUrl -w %{http_code})  

    if [ $TomcatServiceCode -eq 200 ];then  

        echo "[info]页面返回码为$TomcatServiceCode,tomcat启动成功,测试页面正常......"  

    else  

        echo "[error]tomcat页面出错,请注意......状态码为$TomcatServiceCode,错误日志已输出到$GetPageInfo"  
        echo "[error]页面访问出错,开始重启tomcat"  
    # 杀掉原tomcat进程  
        kill -9 $TomcatID  
        sleep 3  
        rm -rf $TomcatCache # 清理tomcat缓存  
        $StartTomcat  

    fi  

  else  

    echo "[error]tomcat进程不存在!tomcat开始自动重启..."  
    echo "[info]$StartTomcat,请稍候......"  
    rm -rf $TomcatCache  
    $StartTomcat  

  fi  

  echo "------------------------------"  
}  

Monitor>>$TomcatMonitorLog 

Answer 1

因为指定了选项-w %{http_code}，当域名不存在或连接超时时，返回的值即为000