scala - How to split string with trailing empty strings in result?

Question

I am a bit confused about Scala string split behaviour as it does not work consistently and some list elements are missing. For example, if I have a CSV string with 4 columns and 1 missing element.

"elem1, elem2,,elem 4".split(",") = List("elem1", "elem2", "", "elem4")

Great! That's what I would expect.

On the other hand, if both element 3 and 4 are missing then:

"elem1, elem2,,".split(",") = List("elem1", "elem2")

Whereas I would expect it to return

"elem1, elem2,,".split(",") = List("elem1", "elem2", "", "")

Am I missing something?

Answer 1

As Peter mentioned in his answer, "string".split(), in both Java and Scala, does not return trailing empty strings by default.

You can, however, specify for it to return trailing empty strings by passing in a second parameter, like this:

String s = "elem1,elem2,,";
String[] tokens = s.split(",", -1);

And that will get you the expected result.

You can find the related Java doc here.