regex - Regular expressions: how to find any word with the form [(non quotation mark)whatever(non quotation mark)]

Question

I want to find any word where it has a square bracke, then no simple quotation mark, then whatever, then no simple quotation mark and then the closed square bracke.

For example, look this words:

['car in the mountain']
[sister in law]
['dog']

The result must show me:

[sister in law]

Exists any regular expression can do it that?

Answer 1

You may use this regex with a negative lookahead:

[(?!'[^]]*'])[^]]*]

RegEx Demo

RegEx Details:

• [: Match starting [
• (?!'[^]]*']): Negative lookahead to fail the match when we have a ' next to [ and just before ]
• [^]]*: Match 0 or more characters that are not ]
• ]: Match closing ]