Should a C++ (implicit or explicit) value constructor accept its parameter(s) by value or reference-to-const, when it needs to store a copy of the argument(s) in its object either way?
Here is the shortest example I can think of:
struct foo {
bar _b;
foo(bar [const&] b) // pass by value or reference-to-const?
: _b(b) { }
};
The idea here is that I want to minimize the calls to bar's copy constructor when a foo object is created, in any of the various ways in which a foo object might get created.
Please note that I do know a little bit about copy elision and (Named) Return Value Optimization, and I have read "Want Speed? Pass by Value", however I don't think the article directly addresses this use case.
Edit: I should be more specific.
Assume that I can't know the sizeof(bar)
, or whether or not bar
is a fundamental, built-in type (bar
may be a template parameter, and foo
may be a class template instead of a class). Also, don't assume that foo
's constructor can be inlined (or bar
's, for that matter). Do assume that I at least might be using a compiler that implements RVO.
What I would like is for there to be a possibility (given compiler optimizations) that a call like this will invoke no calls to bar
's copy constructor whatsoever (even when executing _b(b)
in foo
's initialization list):
foo f = function_that_creates_and_returns_a_bar_object_using_rvo();
Is there any possibility (given the C++98 standard) that this can be done, and if so, is it more or less likely to work if foo
accepts its parameter by reference-to-const instead of by value?
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