Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
720 views
in Technique[技术] by (71.8m points)

bash - How do you start Unix screen command with a command?

According to the docs for the Unix "screen" command, you can configure it in .screenrc to start with a bunch of default screens, each running a command that you specify.

Here's my cofig:

# Default screens
screen -t "shell_0"  1
screen -t "autotest" 2 cd ~/project/contactdb ; autotest

It will not run the autotest command. That window where I'm trying to run autotest just closes instantly when I start screen.

I also tried it with just...

screen -t "autotest" 2 cd ~/project/contactdb

Same result.

I also tried...

screen -t "autotest" 2 ls

Same result there too.

What's the secret to getting it to run a command in a given screen on startup?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Your program is being run (well, except the cd), it's just that it's being run without a parent shell, so as soon as it completes, it exits and you're done.

You could do:

screen -t "autotest" 2 bash -c 'cd ~/project/contactdb ; autotest'

Spawns two shells, but life will probably go on.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...