error handling - Solving a non-linear equation in python

Question

from sympy import Eq, Symbol, solve

v = Symbol('v')
eqn = Eq(0.55**1.3*((3.91/v)-0.01162)*(0.02472*(v-5)+1.132), 0.0)

x = solve(eqn)
print(x)
real_x = [val for val in x if val > 0] 
print(real_x)

NotImplementedError: Unanticipated argument of Eq when other arg is True or False.

What is the actual problem in this code?

Answer 1

等待大神答复