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创建ajax对象 1 //创建对象 2 function createAjax(){ 3 var request =false; 4 //IE浏览器,window对象存在ActiveXObject属性 5 if(window.ActiveXObject){ 6 try{ 7 request = new ActiveXObject("Msxml2.XMLHTTP"); 8 } 9 catch(othermicrosoft){ 10 try{ 11 request = new ActiveXObject("Microsoft.XMLHTTP"); 12 }catch(failed){ 13 request = false; 14 } 15 } 16 } 17 18 //非IE浏览器,window对象存在XMLHttpRequest属性 19 if(window.XMLHttpRequest){ 20 request = new XMLHttpRequest(); 21 22 if (request.overrideMimeType) { 23 request.overrideMimeType("text/xml"); 24 } 25 } 26 return request; 27 } 页面js语句触发事件 1 <input type="text" id="search_input" placeholder="智能搜索" onkeydown="search('total_marks')" onkeyup="result('total_marks')" style="border-color:#32CD32;border-radius:5px;"> 调用的js方法 1 var content = document.getElementById("total_marks").innerHTML; 2 3 function search(id){ 4 5 var search = document.getElementById(id); 6 search.innerHTML = "<div style='margin-left:200px;'>正在搜索...请稍候...</div>"; 7 } 8 9 //获取数据 10 function search_result(){ 11 var ajax = null; 12 // alert(ajax);每次请求都要求使用一个新的XMLHttpRequest 13 14 var div_ajax = document.getElementById("search_input"); 15 var val = div_ajax.value; 16 17 ajax = createAjax(); 18 ajax.onreadystatechange=function(){ 19 // alert(ajax.readyState);//可知当状态值为4时,才能取值 20 if(ajax.readyState == 4){ 21 // alert(ajax.status); 22 if(ajax.status == 200){ 23 var data = ajax.responseText;//数据都返回在responsetext中 24 document.getElementById('total_marks').innerHTML = data; 25 }else{ 26 alert('页面请求失败!'); 27 } 28 } 29 } 30 url = "../bookmarks/js/search.php?key="+val; 31 //如果使用get,就直接通过url直接将数据传给服务器 32 ajax.open("get",url,true); 33 ajax.send(null); 34 35 } 36 37 38 function result(id){ 39 40 if (document.getElementById("search_input").value == "") { 41 document.getElementById(id).innerHTML = window.content; 42 }else{ 43 setTimeout(search_result,1000) 44 }; 45 } 请求的php代码 1 <?php 2 //最好设定字符集,不然在ajax中默认的字符集会导致出错 3 require_once("../db.php"); 4 header("Content-Type:text/html;charset=utf-8"); 5 6 $sql = "SELECT icon,content from bookmarks where title LIKE '%".$_GET['key']."%' order by clicknum"; 7 $result = mysql_query($sql); 8 9 //将多个值存放进数组才能输出,不然会当作一个字符串输出 10 // $arr = array("one"=>"111111","two"=>"222222","three"=>"33333333"); 11 // echo json_encode($arr); 12 ?>
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